5x^2-(-20)=300

Solution for 5x^2-(-20)=300 equation:

5x^2-(-20)=300

We move all terms to the left:

5x^2-(-20)-(300)=0

determiningTheFunctionDomain
5x^2-300-(-20)=0

We add all the numbers together, and all the variables

5x^2-280=0

a = 5; b = 0; c = -280;
Δ = b2-4ac
Δ = 02-4·5·(-280)
Δ = 5600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5600}=\sqrt{400*14}=\sqrt{400}*\sqrt{14}=20\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{14}}{2*5}=\frac{0-20\sqrt{14}}{10}
=-\frac{20\sqrt{14}}{10}
=-2\sqrt{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{14}}{2*5}=\frac{0+20\sqrt{14}}{10}
=\frac{20\sqrt{14}}{10}
=2\sqrt{14}
$